Math Problem Statement
definite integral 0 to 1 of 2/2x^2+3x+1 dx
Solution
We are tasked with solving the definite integral:
Step 1: Simplify the Integral
First, factor the quadratic expression :
Thus, the integral becomes:
Step 2: Partial Fraction Decomposition
To solve the integral, we decompose the fraction into partial fractions:
Multiplying both sides by to eliminate the denominators:
Expanding both sides:
Group the terms by powers of :
Now, equate the coefficients of and the constant term:
From the first equation: .
Substitute into the second equation:
Now, substitute into :
Thus, the partial fraction decomposition is:
Step 3: Integrate the Expression
Now, we can integrate:
The integrals of these forms are straightforward logarithmic integrals:
So, applying this rule:
Now, apply the limits:
[ 2 \left[ \ln(2x + 1) \right]_0^1 - 2 \left[ \ln(x + 1) \right]_0^1 ]
Step 4: Compute the Values
-
For from 0 to 1:
-
For from 0 to 1:
Thus, the result is:
Final Answer:
Would you like further details or clarification?
Here are 5 related questions:
- How do you perform partial fraction decomposition for different types of quadratics?
- Can you apply logarithmic rules to simplify integrals?
- How do integrals change when bounds are negative or involve infinity?
- How can you integrate functions involving higher powers of ?
- What is the role of substitution in definite integrals?
Tip: Always check if a quadratic expression can be factored before attempting partial fractions.
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Math Problem Analysis
Mathematical Concepts
Calculus
Definite Integral
Partial Fraction Decomposition
Logarithmic Integration
Formulas
Integral of 1/(ax + b) = (1/a) * ln|ax + b|
Partial Fraction Decomposition: A/(2x+1) + B/(x+1)
Theorems
Fundamental Theorem of Calculus
Logarithmic Integration
Partial Fraction Decomposition
Suitable Grade Level
College-Level Calculus
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